2024 Czech Amateur Championship - Finishes
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- History
- No later editions →
Finish | Name | Matches won | Frames won | Centuries | Points | Prize money |
---|---|---|---|---|---|---|
Winner | Ales Herout | 5 | 18 (81.82%) of 22 | 1 | 0 | 0 |
Final | Daniel Mily | 8 | 22 (61.11%) of 36 | 0 | 0 | 0 |
Semi-final | Jean-Marie Hustin | 8 | 22 (81.48%) of 27 | 0 | 0 | 0 |
Semi-final | Jan Matejicek | 5 | 16 (69.57%) of 23 | 0 | 0 | 0 |
Quarter-final | Tomas Bejcek | 5 | 14 (53.85%) of 26 | 0 | 0 | 0 |
Quarter-final | Michal Krystof | 4 | 11 (52.38%) of 21 | 0 | 0 | 0 |
Quarter-final | Radim Simecka | 4 | 10 (47.62%) of 21 | 0 | 0 | 0 |
Quarter-final | Jiri Stehlik | 1 | 4 (40%) of 10 | 0 | 0 | 0 |
Group 4 | Jan Svadlenka | 2 | 4 (28.57%) of 14 | 0 | 0 | 0 |
Group 2 | Michal Ciz | 0 | 2 (25%) of 8 | 0 | 0 | 0 |
Group 1 | Petr Zak | 3 | 8 (57.14%) of 14 | 0 | 0 | 0 |
Pre-qualifying Group 1 | Karel Salavec | 0 | 1 (14.29%) of 7 | 0 | 0 | 0 |
Pre-qualifying Group 2 | Pavel Jilek | 1 | 3 (50%) of 6 | 0 | 0 | 0 |
Pre-qualifying Group 2 | Alexej Taf | 0 | 1 (14.29%) of 7 | 0 | 0 | 0 |
Pre-qualifying Group 3 | Bálint Elekes | 0 | 1 (20%) of 5 | 0 | 0 | 0 |
Pre-qualifying Group 4 | Vojtech Marvan | 0 | 0 (0%) of 4 | 0 | 0 | 0 |
Pre-qualifying Group 5 | David Kudelka | 1 | 3 (37.5%) of 8 | 0 | 0 | 0 |
Pre-qualifying Group 6 | Jaroslav Krocil | 0 | 1 (20%) of 5 | 0 | 0 | 0 |
Pre-qualifying Group 7 | Jan Chren | 0 | 2 (33.33%) of 6 | 0 | 0 | 0 |
Pre-qualifying Group 8 | Miroslav Svoboda | 0 | 0 (0%) of 4 | 0 | 0 | 0 |
Pre-qualifying 1 | Rostyslav Bovonenko | 3 | 7 (70%) of 10 | 0 | 0 | 0 |
Pre-qualifying 1 | Pavel Vachalec | 2 | 5 (45.45%) of 11 | 0 | 0 | 0 |
Pre-qualifying 1 | Simon Senkyrik | 1 | 2 (33.33%) of 6 | 0 | 0 | 0 |
Pre-qualifying 1 | Radovan Mrazek | 1 | 2 (28.57%) of 7 | 0 | 0 | 0 |
Pre-qualifying 1 | Frantisek Smekal | 1 | 2 (28.57%) of 7 | 0 | 0 | 0 |
Pre-qualifying 1 | Jiri Zlamany | 1 | 2 (28.57%) of 7 | 0 | 0 | 0 |
Pre-qualifying 1 | Jan Pistek | 1 | 3 (33.33%) of 9 | 0 | 0 | 0 |
Withdrew | Jaroslav Horni | 2 | 4 (100%) of 4 | 0 | 0 | 0 |